Buffer Preparation FAQs
What does “buffer molarity” mean?
For example, 1 L of ammonium acetate (buffer 20, mM pH 4.0) will be prepared the following way: 100 mmol of ammonium acetate salt is dissolved in a little less than 1000 mL of water, the acidity of the solution is adjusted to pH=4.0 by (adding) acetic acid and total volume is adjusted to 1000 mL with water. In this example, the molarity of the buffer is based on molarity of ammonia. The concentration of the acetic acid is unknown. Take 200mL of your prepared solution and adjust it up to 1000mL with your mobile phase.
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Dissolve the solid ammonium formate salt in formic acid 10% w/v. This is a buffer stock solution. Then use this stock solution to prepare whatever mobile phase is needed. Let’s say we need 1L of 10% MeOH with 90% MeCN, 1% Formic Acid and 0.1% AmFm. The mixture will consist of 890 mL of MeCN, 100 mL of MeOH, and 10 mL of buffer solution. Another example, 1L of 50% MeOH with 50% MeCN, 0.5% Formic Acid and 0.05% AmFm. The mixture will consist of 495 mL of MeCN 500 ml of MeOH and 5 mL of buffer solution.
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